scala - How to use a Filtered Service with RoutingService in Finagle -


fair warning, i'm new scala, missing simple here.

i have code, works great

import java.net.inetsocketaddress  import com.twitter.finagle.builder.server import com.twitter.finagle.builder.serverbuilder import com.twitter.finagle.http.http import com.twitter.finagle.http.request import com.twitter.finagle.http.richhttp import java.util.logging.logger import com.typesafe.config.configfactory import org.jboss.netty.buffer.channelbuffers.copiedbuffer import org.jboss.netty.util.charsetutil.utf_8 import com.twitter.finagle.service import com.twitter.finagle.http.response import com.twitter.util.future import com.twitter.finagle.http.service.routingservice import org.jboss.netty.handler.codec.http.httpresponse import org.jboss.netty.handler.codec.http.httprequest import com.twitter.finagle.simplefilter  object testserver extends app {      val myservice = new service[request, response] {                 def apply(request: request) = {                     // if throw exception here, filter catch it.                     // throw new runtimeexception("s")                     future {                         val response = response()                                 response.setcontent(copiedbuffer("hello world", utf_8))                                 response                     }                 }             }              val routingservice = routingservice.bypath {                 case "/" => myservice             }      val server: server = serverbuilder()             .codec(richhttp[request](http()))             .bindto(new inetsocketaddress(8080))             .name("httpserver")             .build(routingservice)      println("server up.")      class authorize extends simplefilter[httprequest, httpresponse] {         def apply(request: httprequest, continue: service[httprequest, httpresponse]) = {             println("filtered")             continue(request)     } }  }

but want add authorize filter service. if add this:

val authorize = new authorize val aservice: service[httprequest, httpresponse] = authorize andthen myservice

i compilation error:

[error]  found   : com.twitter.finagle.service[com.twitter.finagle.http.request,com.twitter.finagle.http.response] [error]  required: com.twitter.finagle.service[org.jboss.netty.handler.codec.http.httprequest,org.jboss.netty.handler.codec.http.httpresponse]

if change service type service[httprequest, httpresponse], can't use routingservice. 

[error]  found   : com.twitter.finagle.service[org.jboss.netty.handler.codec.http.httprequest,org.jboss.netty.handler.codec.http.httpresponse] [error]  required: com.twitter.finagle.service[?,com.twitter.finagle.http.response]

due these type errors, having hard time getting routing service work filters.

thanks!

edit:

i wanted add example of code working using @septem's answer below, use filter:

class authorize extends filter[request, response, request, response] {         def apply(request: request, continue: service[request, response]) = {             println("filtered")             continue(request)         }     }

i'm stilla little hazy on finagle , scala- guess happening here using simplefilter assumed service of type,

why use different request , response types in service , filter?

your service using request , response finagle:

val myservice = new service[request, response]

but filter using request , response netty:

class authorize extends simplefilter[httprequest, httpresponse]

i think reason compliation error, have choose 1 satisfies need, , stick it.

--edit--

then think should implement filter base on filter instead of simplefilter

abstract class filter[-reqin, +repout, +reqout, -repin] extends ((reqin, service[reqout, repin]) => future[repout])

the abstract class filter allow transform request/response types

check out doc details


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