javascript - console.log without arguments? How does this work? -

probably basic question haven't found answer in docs or google...

i doing nodeschool's "learnyounode" module, , intro http client question found official answer used console.log without arguments (and indeed args in function, understand) :

var http = require('http')  http.get(process.argv[2], function (response) {       response.setencoding('utf8')       response.on('data', console.log)       response.on('error', console.error)   }) 

how work? looks clean , obvious, i'm not sure can use style confidently without better understanding what's going on.

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btw comparison (and see i'm not understanding), here's own similar, longer answer:

var http = require('http');  http.get(process.argv[2], function callback(response) {     response.setencoding('utf8');     response.on('data', function(data) {         console.log(data);     });     response.on('error', function(error) {         console.error(error);     }); }); 

it's pretty simple @ code

response.on('error', function(error) {      console.error(error);  }); 

what did there wrote callback passed object error event can use error then.

now let @ other code

response.on('error', console.error) 

the same happening event passes it's object callback function console.error here takes 1 or more objects.

so like

let mylog = function(datatolog) {     console.log(datatolog); }  response.on('error', mylog); 

would work, hope makes bit clearer.