php - Broken switch statement -


ive been searching , staring hours , i'm @ loss. have following code when august date passed through switch (as aug) statement keeps returning 0 value instead of 8. echo results below code block. ideas might going wrong? seemed work july , broke on august 1st.

$when=date("y-m-d");     $created=date("ymd");     $date=explode('-',$emprow->hire_date);     echo "<br>hire date ";print_r($date);echo "<br>";     switch ($date[1])     {         case "jan":             $date[1]=01;             break;         case "feb":             $date[1]=02;             break;         case "mar":             $date[1]=03;             break;         case "apr":             $date[1]=04;             break;         case "may":             $date[1]=05;             break;         case "jun":             $date[1]=06;             break;         case "jul":             $date[1]=07;             break;         case "aug":             $date[1]=08;             break;         case "sep":             $date[1]=09;             break;         case "oct":             $date[1]=10;             break;         case "nov":             $date[1]=11;             break;         case "dec":         case "dec":             $date[1]=12;             break;     }     echo "<br>hire date ";print_r($date);echo "<br>";     $startdate=sprintf("%04d%02d%02d",$date[2],$misc->getmonthnum($date[1]),$date[0]);

which results in following:

hire date array ( [0] => 05 [1] => aug [2] => 2013 )

hire date array ( [0] => 05 [1] => 0 [2] => 2013 )

startdate date 20130005

i verified put in comments.

08 non-existant octal number. use "08" or 8

you can pad zeros when you're ready output it.

here's illustration of what's going on in php original code:

$date[1]=08; echo $date[1]; echo ' | '; $date[1]=010; echo $date[1];

output:

0 | 8

-

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