c - Wanting to deference my array contents to zero. Only first number in array changes to zero -

i new stackoverflow , c , have question. required write program iterate through array, , dereference contents zero. reason, "zero_out_array" change first number in array zero, , not rest. here code, appreciated.

#include <stdio.h>  void print_array(int* p_array, int num_elements) {     printf("print_array called:\n");      (int = 0; < num_elements; i++)     {         printf("%d \n", p_array[i]);     } }  void zero_out_array(int* p_array, int num_elements) {     printf("zero_out_array called:\n");      *p_array = 0;      (int j = 0; j < num_elements; j++)     {         printf("%d \n", p_array[j]);     } }  int main() {     int main_array[] = { 15, 24, 33, 42, 51 };      print_array(main_array, 5);      zero_out_array(main_array, 5);      return 0; } 

please consider code modified below:

#include <stdio.h>  void print_array(int* p_array, int num_elements) {     printf("print_array called:\n");      (int = 0; < num_elements; i++)     {         printf("%d \n", p_array[i]);     } }  void zero_out_array(int* p_array, int num_elements) {     printf("zero_out_array called:\n");      *p_array = 0;      for(int j = 0; j < num_elements; j++)         *(p_array+j)=0;      (int j = 0; j < num_elements; j++)     {         printf("%d \n", p_array[j]);     } }  int main() {     int main_array[] = { 15, 24, 33, 42, 51 };      print_array(main_array, 5);      zero_out_array(main_array, 5);      return 0; } 

in above code, have added loop:

for(int j = 0; j < num_elements; j++)         *(p_array+j)=0; 

*p_array points first element of array, have used loop change elements. doing *(p_array+j)=0, iteratively visiting array elements , making them 0.